WebSolution Verified by Toppr Correct option is C) Let P CO2=x atm P CO=10P CO2=10x atm The equilibrium constant K p= P CO2P CO2 63= x(10x) 2 63x=100x 2 100x 2−63x=0 This is quadratic equation with solution x= 2a−b± b 2−4ac 63 x= 2(100)−(−63)± (−63) 2−4(100)(0) x= 20063±63 x=0 or x=0.63 But partial pressure cannot be 0. Hence, P CO2=x=0.63 atm WebTextbook solution for AP* Chemistry: The Central Science (NASTA Edition) 14th Edition Brown and Lemay Chapter 15 Problem 15.49E. We have step-by-step solutions for your textbooks written by Bartleby experts!
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WebFor the reactionH2 (g)+I2 (g)2HI (g), consider two possibilities: (a) you mix 0.5 mole of each reactant. allow the system to come to equilibrium, and then add another mole of H2 and … WebAnswer (1 of 3): first we should write the Kc for this reaction Kc = [CO]*2 / [CO2] 1.5 x 10*-24 = [CO]*2 / 0.005 mol/L [CO] = 8.66 x 10*-14 mol/L batman poison ivy kiss
Solved [References] Consider the following reaction at - Chegg
WebFor the reactionH2 (g)+I2 (g)2HI (g), consider two possibilities: (a) you mix 0.5 mole of each reactant. allow the system to come to equilibrium, and then add another mole of H2 and allow the system to reach equilibrium again. or (b) you mix 1.5 moles of H2 and 0.5 mole of I2 and allow the system to reach equilibrium. WebTitanium which is used to make air plane engines and frames, can be obtained from titanium tetrachloride, which in turn is obtained from titatnium oxide by the following process: 3TiO2(s) + 4C (s)+ 6Cl2(g) 3TiCl4(g) + 2CO2g) + 2CO(g) A vessel contains 4.15 g of TiO2, 5.67 g C and ; 6.78 g Cl2, suppose the reaction goes to completion as written ... WebExpert Answer 100% (11 ratings) Transcribed image text: [References] Consider the following reaction at 725°C: C (s) + CO2 (g) = 2CO (g) At equilibrium, a 4.50-L container has 2.6 g of carbon, CO2 at a partial pressure of 0.0024 atm, and a total pressure of 0.627 atm. Calculate Kp for this reaction at 725°C. Kp = Previous question Next question batman ninja animation studio